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0=x^2+10x+15
We move all terms to the left:
0-(x^2+10x+15)=0
We add all the numbers together, and all the variables
-(x^2+10x+15)=0
We get rid of parentheses
-x^2-10x-15=0
We add all the numbers together, and all the variables
-1x^2-10x-15=0
a = -1; b = -10; c = -15;
Δ = b2-4ac
Δ = -102-4·(-1)·(-15)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{10}}{2*-1}=\frac{10-2\sqrt{10}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{10}}{2*-1}=\frac{10+2\sqrt{10}}{-2} $
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